最简单的临时处理方式是在当前目录下python -m http.server

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from flask import Flask, send_from_directory
import os

app = Flask(__name__)

root_dir = r'C:/Users/tellw'

def root_dir_file_list():
    file_list_str = ''
    for filename in os.listdir(root_dir):
        if os.path.isdir(root_dir+'/'+filename):
            li = f'''
            <li><a href="/{filename}/">{filename}/</a></li>'''
        else:
            li = f'''
            <li><a href="/{filename}">{filename}</a></li>'''       
        file_list_str = file_list_str + li
    return file_list_str

def sub1_dir_file_list(folder):
    if folder[-1] == '/':
        folder = folder[:-1]
        print(folder)
    file_list_str = ''
    for filename in os.listdir(os.path.join(root_dir,folder)):
        if os.path.isdir(os.path.join(folder,filename)):
            tail='/'
        else:
            tail=''
        li = f'''
        <li><a href="/{folder}/{filename}{tail}">{filename}{tail}</a></li>'''
        file_list_str = file_list_str + li
    return file_list_str

def create_html(file_list_str):
    html = f'''
        <html>
        <head>
            <title>Download</title>
            <meta name="viewport" content="width=device-width,initial-scale=1.0"/>
        </head>
        <body>
        <h1>Directory listing</h1>
        <hr>
        <ul>
        {file_list_str}
        </ul>
        </body>
    </html>
    '''
    return html


@app.route('/')
def index():
    return create_html(root_dir_file_list())


@app.route('/<path:sub_dir>')
def sub_dir1_page(sub_dir):
    # dir_name = root_dir + '/' + sub_dir
    return create_html(sub1_dir_file_list(sub_dir))

@app.route('/<filename>')
def download_root(filename):
    return send_from_directory(root_dir, filename)

@app.route('/<path:sub_dir>/<filename>')
def download_subdir1(sub_dir, filename):
    dir_name = root_dir + '/' + sub_dir
    return send_from_directory(dir_name, filename)

app.run(host='0.0.0.0',debug=True)
用url是否以'/'结尾区分“目录+目录”和“目录+文件”的路由，且以'/'结尾的链接文字表示要访问的是个目录，没有'/'结尾的链接文字表示要下载那个文件，无论目录有多少层，都能访问，path变量把所有的路径字符串全部接收，然后处理文件系统。

代码的思路来自flask学习笔记(三)：文件浏览器+下载指定文件夹中的文件(包含子文件夹)

使用nginx配置文件下载站点，且没有层级限制

nginx配置文件的http块里添加如下代码

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server {
        listen       8085;
        server_name  localhost;
        autoindex on;

        #charset koi8-r;

        #access_log  logs/host.access.log  main;

        location / {
            root   C:/Users/tellw;
            # index  index.html index.htm index.php;
        }

        #error_page  404              /404.html;

        # redirect server error pages to the static page /50x.html
        #
        error_page   500 502 503 504  /50x.html;
        location = /50x.html {
            root   C:/Users/tellw/blog;
        }

        # proxy the PHP scripts to Apache listening on 127.0.0.1:80
        #
        location ~ \.php$ {
            root C:/Users/tellw/blog;
            #proxy_pass   http://127.0.0.1;
            # php 处理程序监听的tcp端口
            fastcgi_pass 127.0.0.1:9000;
            fastcgi_index index.php;
            # 确定脚本名称
            fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
            # 传递请求参数
            fastcgi_param QUERY_STRING $query_string;
            # 必须要包含fastcgi_params预定义参数
            include fastcgi_params;
        }

        # pass the PHP scripts to FastCGI server listening on 127.0.0.1:9000
        #
        #location ~ \.php$ {
        #    root           html;
        #    fastcgi_pass   127.0.0.1:9000;
        #    fastcgi_index  index.php;
        #    fastcgi_param  SCRIPT_FILENAME  /scripts$fastcgi_script_name;
        #    include        fastcgi_params;
        #}

        # deny access to .htaccess files, if Apache's document root
        # concurs with nginx's one
        #
        #location ~ /\.ht {
        #    deny  all;
        #}
    }

随后进入nginx目录，nginx -s reload重启nginx服务，访问http://localhost:8085，即可看到C:/Users/tellw目录下的文件浏览站点。

参考链接：通过nginx进行文件共享

创建于2023.3.23/18.36，修改于2023.6.7/17.33